Could somebody please help me solve part b?
Suppose f is differentiable and grad f (-2,5) = -3i + 4j (i and j are vectors), and f (-2,5) = 1.
a) Give the equation of the tangent plane to the graph of f at x = -2, y = 5.
answer :
m = -3 (slope of x) and n = 4 (slope of y)
so equation of the tangent plane to f(-2,5) = -3(x+2) + 4(y-5) + 0(z-0)
= -3x + 4y - 26 = 0
b) Give the equation of the tangent line to the contour for f at x = -2, y = 5.
?????? (contour for f at x = -2, y = 5 is 1 I believe)
Suppose f is differentiable and grad f (-2,5) = -3i + 4j (i and j are vectors), and f (-2,5) = 1.
a) Give the equation of the tangent plane to the graph of f at x = -2, y = 5.
answer :
m = -3 (slope of x) and n = 4 (slope of y)
so equation of the tangent plane to f(-2,5) = -3(x+2) + 4(y-5) + 0(z-0)
= -3x + 4y - 26 = 0
b) Give the equation of the tangent line to the contour for f at x = -2, y = 5.
?????? (contour for f at x = -2, y = 5 is 1 I believe)